Chapter 9: Chemical Quantities
Main Concept: Stoichiometric Problems
This Website further explains stoichiometry:
This is an Activity for stoichiometry:
This Calculation explains how to do a stoichiometric equation:
- Stoichiometry - the process of using a chemical equation to calculate the relative masses of reactants and products involved in a reaction
This Website further explains stoichiometry:
This is an Activity for stoichiometry:
This Calculation explains how to do a stoichiometric equation:
This video further explains stoichiometry:
Main Concept: Limiting and Excess Reagent
This Website explains limiting and excess reagents:
This Activity has problems that have to do with limiting and excess reagents:
This Calculation demonstrates a limiting and excess reagent problem:
- Limiting Reactant - the reactant that runs out first and thus limits the amounts of products that can form
- Excess Reactant - the largest out of the compound
This Website explains limiting and excess reagents:
This Activity has problems that have to do with limiting and excess reagents:
- http://chemcollective.org/activities/tutorials/stoich/limiting-reagents
- http://www.armoredpenguin.com/crossword/Data/2011.03/2020/20202259.361.html
This Calculation demonstrates a limiting and excess reagent problem:
This video explains limiting and excess reagents
Main Concept: Percent Yield
Calculations:
LiOH + CO2 -> Li2CO3 + H2O
How many moles of Li2CO3 will be formed with 1000g of LiOH? Give percent yield.
Answer- 2LiOH + CO2 -> Li2CO3 + H2O
1000.00 g LiOH x 1 mol LiOH/23.95 g LiOH x 1 mol Li2CO3/2 mol LiOH
20.9 mole Li2CO3
10.1/20.9x100=48%
This Website explains percent yield:This Activity has problems with percent yield:
This video explains percent yield:
- Actual Yield - the amount of product actually obtained
- Theoretical Yield - the amount of product obtained in a chemical reaction
- The actual yield and theoretical yield are usually compared
Calculations:
LiOH + CO2 -> Li2CO3 + H2O
How many moles of Li2CO3 will be formed with 1000g of LiOH? Give percent yield.
Answer- 2LiOH + CO2 -> Li2CO3 + H2O
1000.00 g LiOH x 1 mol LiOH/23.95 g LiOH x 1 mol Li2CO3/2 mol LiOH
20.9 mole Li2CO3
10.1/20.9x100=48%
This Website explains percent yield:This Activity has problems with percent yield:
This video explains percent yield: